Joey is running an experiment with a mass on a spring. Joey models the height of the mass above the table he is working on using the equation

h(t)=6.85cos(3.42t)+9

, where the height is in inches and the time, t,
is in seconds since he let the mass free. How many seconds, to the nearest tenth, will it take for the mass to
return to its original position?

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

hope to and hope that my answer is brainliest.(follow me )

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