What are the zeros of y = x^2 + 9x +14?

Step-by-step explanation:

obtain zeros P(x)=x  2

+9x+14

→ for zeros find P(x) = 0

x  

2

+9x+14=0

x  

2

+7x+2x+14=0

x(x+7)+2(x+7)=0

(x+7)(x+2)=0

x=−7 or x=−2

zeros is -7 & -2

→P(−7)=(−7)  

2

+9(−7)+14

=+49−63+14

=0

→P(−2)=(−2)  

2

+9(−2)+14

=4−18+14

=0

x= -7,x= -2

The zerores of polynomial y are -2 & -7

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~