According to a recent survey, the average time patients spen waiting in an emergency room is 6 hours. Assuming the distribution is normal and the standard deviation is 1.5 hours, what is the probability that a randomly selected patients pends less than 3 hours waiting in an emergency room? Use the Standard Normal Table to determine the probability.

391.6 is the correct answer

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation: