Please help

h(t)=-t²+12t+5​

Step-by-step explanation:

nate form assuming t is real:

h(t) + (t - 12) t = 5

Alternate forms:

h(t) = 5 - (t - 12) t

h(t) + t^2 = 12 t + 5

Roots:

t = 6 - sqrt(41)

t = 6 + sqrt(41)

Properties as a real function:

Domain

R (all real numbers)

Range

{h element R : h<=41}

Derivative:

d/dt(-t^2 + 12 t + 5) = -2 (t - 6)

Indefinite integral assuming all variables are real:

integral(-t^2 + 12 t + 5) dt = -t^3/3 + 6 t^2 + 5 t + constant

Global maximum:

max{-t^2 + 12 t + 5} = 41 at t = 6

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b