A particular bug's population will continuously grow at 5.8% where time is measured in months. A scientist started with 820 of these bugs. Using the Continuous Growth Formula: F=Pert find, how many bugs will there be in 34.6 months?

step-by-step explanation:

3024 rhe base is what up in worry about

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

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нσρє ι ¢συℓ∂ нєℓρ υ

1/4 is the asnwer cuz 5/20 is the faction