Mathematics, 01.05.2021 06:30 gensevilla54
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t^2 + 19.6t + 58.8,
where s is in meters. How high will the object be after 2 seconds?
194. 04 feet
117.6 feet
78.4 feet
1.96 feet
pls help 20 points tyy
Answers: 3
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An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation...
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