A wall in a classroom has a length of 16 ft and a diagonal of 20 ft. A student is painting a rectangular mural on the wall. The mural has a length of 6 ft and a diagonal of 10 ft. What is the difference between the width of the wall and the width of the mural? ill mark you brainliest pls help!
Answer choices:
A. 2ft
B. 4ft
C. 10ft
D. 14ft

B. 4 ft

Step-by-step explanation:

First, find the width of the wall.

The length, width, and diagonal form a right triangle, where the diagonal is the hypotenuse and the length and width are the 2 legs.

Use the pythagorean theorem and solve for a, the width of the wall.

a² + b² = c²

a² + 16² = 20²

a² + 256 = 400

a² = 144

a = 12

So, the width of the wall is 12 feet.

Solve for the width of the mural. Again, the diagonal, length, and width form a right triangle.

Use the pythagorean theorem again and solve for a, the width of the mural:

a² + b² = c²

a² + 6² = 10²

a² + 36 = 100

a² = 64

a = 8

So, the width of the mural is 8 feet.

Now, find the difference between the widths of the wall and mural:

12 - 8

= 4

So, the difference between the two widths is B. 4 ft

it would be:

c.parallelogram.

idk

step-by-step explanation: i just don't