Mathematics, 29.04.2021 23:30 soriajimmy85

Use a net to find the surface area of the cylinder. Use 3.14 for $\pi$ .

Use a net to find the surface area of the cylinder. Use 3.14 for .

Answers: 1

Show answers

Other questions on the subject: Mathematics

Mathematics, 21.06.2019 13:20, Riplilpeep

Mr. walker gave his class the function f(x) = (x + 3)(x + 5). four students made a claim about the function. each student’s claim is below. jeremiah: the y-intercept is at (15, 0). lindsay: the x-intercepts are at (–3, 0) and (5, 0). stephen: the vertex is at (–4, –1). alexis: the midpoint between the x-intercepts is at (4, 0). which student’s claim about the function is correct?

Answers: 2

continue

Mathematics, 21.06.2019 17:30, QueenNerdy889

Suppose that an airline uses a seat width of 16.516.5 in. assume men have hip breadths that are normally distributed with a mean of 14.414.4 in. and a standard deviation of 0.90.9 in. complete parts (a) through (c) below. (a) find the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.516.5 in. the probability is nothing. (round to four decimal places as needed.)

Answers: 3

continue

Mathematics, 21.06.2019 21:00, Anybody6153

Ariana starts with 100 milligrams of a radioactive substance. the amount of the substance decreases by 20% each week for a number of weeks, w. the expression 100(1−0.2)w finds the amount of radioactive substance remaining after w weeks. which statement about this expression is true? a) it is the difference between the initial amount and the percent decrease. b) it is the difference between the initial amount and the decay factor after w weeks. c) it is the initial amount raised to the decay factor after w weeks. d) it is the product of the initial amount and the decay factor after w weeks.

Answers: 1

continue

Mathematics, 21.06.2019 21:10, jaki9

Consider circle o, where and . m∠bpd °. °.

Answers: 3

continue

You know the right answer?

Use a net to find the surface area of the cylinder. Use 3.14 for .
...