The sum of the squares of three consecutive integer numbers is 1454. Find the numbers. I have already found 21 22 23 but the question says that there are 2 possibilities. please help

three consecutive integers

Let x,(x+1),(x+2) represent the three consecutive integers

Question states

x^2 +(x+1)^2+(x+2)^2 = 110

Solving for x

3x^2 + 6x  + 5 = 110

3x^2 + 6x  -105 = 0

3(x^2 + 2x - 35)  = 0

 (x^2 + 2x - 35)  = 0  

factoring

 (x+7)(x-5) = 0 Note: SUM of the inner product(7x) and the outer product(-5x) = 2x

 (x+7)=0  |x = -7  The three consecutive integers are -5,-6,-7

 (x-5)=0  |x = 5   The three consecutive integers are 5,6,7

25 + 36 + 49 = 110  

i dont think there is anymore answers

Step-by-step explanation:

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.