A farmer has collected data from one of his crops. Suppose the farmer found that the number of seeds, () S
(
t
)
, produced by a plant maturing at age
t
(in weeks) was
()=24
S
(
t
)
=
t
2
4
seeds per mature plant.
Further, the farmer discovered that only
()=11.76−24+3961.752+764.8
P
(
t
)
=
11.76
−
t
2
4
+
3961.75
t
2
+
764.8
t
plants matured to age
t
.
Determine the maximum rate of change of the crop's seed production. (answers rounded down)

7 weeks

step-by-step explanation:

convert each fraction to the least common multiple of 20, so 3/4 = 15/20 & 1/10 = 2/20, then divide 15 by 2 and you get a little over 7, so the food will last 7 weeks.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.