A heavy piece of equipment has wheels on one side and legs on the other as shown in the diagram below. Two people are trying to move the equipment. Each person grabs a handle and begins to lift. The first person imparts an upward force of 300 N and the second person imparts an upward force of 290 N. This is enough to lift the side of the equipment, but they also need to get it moving.
While maintaining the upward forces, the first person imparts a horizontal force of 185 N and the second person a horizontal force of 205 N. They maintain these forces while the equipment begins to move.

What is the total force in the horizontal direction?
_ N   

What is the total force in the upward direction?
_ N   

Determine the magnitude and direction of this resultant vector (the resultant vector from combining the forces of the two people).

Magnitude: _ N   

Direction: _ °   

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d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24

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step-by-step explanation:

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answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.