The side length of thr hexagon is 16 centimeters, and the length of the digonal shown is 32 centimeters. Charles measured the height of one of trapezoids and found that the height of one of the trapezoids and found that the height was 13.9 centimeters. Find the area of the hexagon.

669cm2

correct question

Charles drew a regular hexagon and divided it into two identical trapezoid , the side length of the hexagon iscoming16cm,the diagonal shown in fig 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the area

Step-by-step explanation:

The side length of the hexagon should be given which is 16 cm

To get the Length the side length makes with the height of the trapezium, Pythagoras theorem is applied to get the base of the triangle

Base = √((16)^2 - (13.9)^2

Base = √62.29

Base = 7.92cm

Since we have gotten the base

Diagonal - the base gives the top length of the trapezium.

32- 7.92- 7.92 = 16.16

The area of the hexagon gives the 2 times of the trapezium.

To find the area of the trapezium

= 1/2 * ( a+b)h

= 1/2* ( 32+ 16.16)* 13.9

= 24.04*13.9

Area of the trapezium = 334.71cm2

= 334.71 * 2

= 669.42cm2

Hope this helps

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

i am not sure :

step-by-step explanation: