Review the proof of Tangent (A minus B) = StartFraction tangent A minus tangent B Over 1 + (tangent A) (tangent B) EndFraction. tan(A – B) =

Step 1: Equals StartFraction sine (A minus B) Over cosine (A minus B) EndFraction

Step 2: Equals StartFRaction sine A cosine B minus cosine A sine B Over cosine A cosine B + sine A sine B EndFraction

Step 3: Equals StartStartFraction StartFraction sine A cosine B minus cosine A sine B Over blank EndFraction OverOver StartFraction cosine A cosine B + sine A sine B Over blank EndFraction EndEndFraction

Step 4: Equals StartFraction tangent A minus tangent B Over 1 + (tangent A) (tangent B)

To complete step 3, which expression must fill in each blank space?

the 3rd option is right

step-by-step explanation:

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: