Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0≤θ<360. P=\left(\frac{\sqrt{2}}{2},-\frac{\ sqrt{2}}{2}\right)
P=(
2
2
​

​
,−
2
2
​
ANSWER___
θ=360−45=315
-delta math

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