The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point (1, 8). Find a, b and c
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Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be

Now all you have to do is solve for a.  You know that the vertex is and you have know the point of .  Now, all you have to do is plug in these values and solve for a.

Now you know the equation is , but you need it in quadratic form.  All you have to do is solve is distribute the 6:

You get:

a = 6

b = 0

c = 2

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: