( PLEASE HELP ) The Perez family is researching the cost of keeping their dog at a kennel during an upcoming vacation. The local kennel allows “Silver” families to pay a rate of $36 per day. For a fee, families can buy a “Gold” membership and will be allowed to board their dogs at a discounted rate as shown in the table. Total Cost, Including Membership Fee, to Board a Dog
Type of membership
1 Day
2 Days
7 Days
Silver
$36
$72
$252
Gold
$70
$90
$190

What is the cost of a Gold membership?
$20
$34
$50
$70

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )

for future students the answer is b

hope i

-lavira: )

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.