Which equation has a constant of proportionality equal to 222? Choose 1
Choose 1

(Choice A)
A
y=\dfrac{10}{5}xy=
5
10
​
xy, equals, start fraction, 10, divided by, 5, end fraction, x

(Choice B)
B
y=\dfrac{2}{2}xy=
2
2
​
xy, equals, start fraction, 2, divided by, 2, end fraction, x

(Choice C)
C
y=\dfrac{2}{4}xy=
4
2
​
xy, equals, start fraction, 2, divided by, 4, end fraction, x

(Choice D)
D
y=\dfrac{22}{2}xy=
2
22
​
x

i can you with this question sweetie!

step-by-step explanation:

15 batches are the most you can make

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

(-5,-28)

i graphed to on desmos.