Graph a line with a slope of -3 that contains the point (4, -2). (Just tell me where to put the points please)​

(4, -2),  (3, 7),  (5, 1),  (6, -2),  (7, -5)

Step-by-step explanation:

These are a few of the points, so you can just connect them!

Hope this helped! :)

Step-by-step explanation:

If you have both the slope and a point on the line, use the point-slope formula y - k = m(x - h), which here is y + 2 = -3(x - 4).

Now you can choose a few x values at random and calculate the associated y values.  Let's try x = -1, x = 3, x = 0:

For x = -1:  y + 2 = -3(-1 - 4), or y = -2 -3(-5) = -2 + 15 = 13.  The point is (-1, 13).

For x = 3, we get y + 2 = -3(-1), or y = -2 + 3 = 1.  The point is (3, 1).

For x = 0, y = -2 - 3(-4), or y = -2 + 12 = 10.  The point is (0, 10).

Plot these three points and draw a line through them.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

ur right ive taken the test

step-by-step explanation: