Independent Practice Find the second, fifth, and ninth terms of each sequence.

an=−5+(n−1)7a subscript n baseline equals negative 5 plus left parenthesis n minus 1 right parenthesis 7

A.
–4, –1, 3

B.
7, 28, 72

C.
12, 33, 61

D.
2, 23, 51

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

sorry i got nothing

step-by-step explanation:

answer: idk

step-by-step explanation: