Evaluate the function below for x = 4.
F(x) = x3 + 2x2 + 1

reation garne and same nikalne huss

77

Step-by-step explanation:

Plug in:

F(4) = (4)3 + 2(4)2 + 1

F(4) = 12 + (8)^2 + 1

F(4) = 12 + 64 + 1

F(4) = 77

(assuming 2x2 = 2x squared)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: