Independent Practice A Bicyclist's Practices

Elaspsed TimeDistance

10 min3 mi

25 min7.5 mi

A bicyclist traveled at a constant speed during a timed practice period. Write an equation and find the distance the cyclist traveled in 30 min.

A.
d = 0.3t; 9 mi

B.
d = 30t; 900 mi

C.
d= 10/3t; 100 mi

D.
d = 3t; 90 mi

Arrange the steps to solve this system of linear equations in the correct sequence. x + y = -2 2x – 3y = -9 tiles subtract 3x + 3y = -6 (obtained in step 1) from 2x – 3y = -9 (given) to solve for x. substitute the value of x in the first equation (x + y = -2) to get y = 1. the solution for the system of equations is (-3, 1). x = -15 the solution for the system of equations is (-15, 13). add 3x + 3y = -6 (obtained in step 1) to 2x – 3y = -9 (given), and solve for x. x = -3 substitute the value of x in the first equation (x + y = -2) to get y = 13. multiply the first equation by 3: 3(x + y) = 3(-2) 3x + 3y = -6.