Nita graphed the system of equations on the graph below. y = negative 3 (x + 2). Y = negative 3 x minus 6.

On a coordinate plane, a line goes through (negative 2, 0) and (negative 1, negative 3).

Which explains why there is only one line?
Each has a slope of –3 and a y-intercept of –6, so the system has infinitely many solutions.
Each has a slope of –3 and a y-intercept of –6, so the system has no solution.
Each has a slope of –3, but one has a y-intercept of 2 and the other has a y-intercept of –6. So, the system has infinitely many solutions.
Each has a slope of –3, but one has a y-intercept of 2 and the other has a y-intercept of –6. So, the system has no solution.

answer

106 emergencies

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft