1.)a rectangle has an area of 72 square centimeters and the length is twice the width. the perimeter of the rectangle

2.)if sides of a square are increased by 4 cm, the area is increased by 40 cm^2. find the length of a side of the original square.

the topic is system of linear equations with two variables

give me the solution

1.

area = L x w = 72

L = 2w

72 = 2w*w = 2w^2

divide by 2

36 = w^2

w = sqrt(36) = 6 

l = 2*6 =12

perimeter = 2L +2W = 2*12 + 2*6 = 24+12 = 36

2.

sqrt(40)= 6.324555 cm ( round to 6.32 )

6.32 - 4 = 2.32 cm original length of a side

ege

step-by-step explanation:

egge

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2