What is the initial value of the equation shown? y = −7x − 6

y = f(x)

initial value = x=0

F(0) = -7x-6

f(0) = -7(0) -6 = 0-6 = -6

 answer is -6

Step-by-step explanation:

we  know that

The initial value is the value of the function when the value of x is equal to zero

The initial value is the y-intercept of the function

In this problem we have

-----> equation of the line into slope intercept form

therefore

-----> the slope

----> the y-intercept

The initial value is

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

it would rotate about 180 degrees.