Aship travels 200 miles due west, then adjusts its course 30° north of west. the ship continues on this course for 30 miles. approximately how far is the ship from where it began?
103.1 mi.
174.7 mi.
214.7 mi.
226.5 mi.

If the ship travels 30° north of west, then the ship moves to the north a certain distance, and to the west a certain distance.

north: 30 miles X sin(30) = 15 miles

west: 30 miles X cos(30) = 26 miles

The distance north is 15 miles.

The total distance west is 226 miles.

We can use the Pythagorean theorem to find the distance from the point where the ship began.

distance = sqrt(15^2+226^2)

distance = sqrt(51301)

distance = 226.5 miles

The distance from the starting point is 226.5 miles.

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )