![\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\ -------------------------------\\\\ \sqrt{16-x^2}\implies \sqrt{16-[4sin(x)]^2}\implies \sqrt{16-[4^2sin^2(x)]} \\\\\\ \sqrt{16-16sin^2(x)}\implies \sqrt{16[1-sin^2(x)]}\implies \sqrt{16cos^2(x)} \\\\\\ \sqrt{4^2cos^2(x)}\implies \sqrt{[4cos(x)]^2}\implies 4cos(x)](/tpl/images/0418/7279/8ebb0.png)
Simplify the expression: sqrt(16 − x^2)
as much as possible after substituting "4 sin x" for...
Mathematics, 14.12.2019 15:31 janelle3496
Simplify the expression: sqrt(16 − x^2)
as much as possible after substituting "4 sin x" for x.
Answers: 1
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