An earthquake registered 7.4 on the richter scale. if the reference intensity of this quake was 2.0 × 1011, what was its intensity?

The intensity was

Step-by-step explanation:

We are given

An earthquake registered 7.4 on the Richter scale

so, RC=7.4

the reference intensity of this quake was 2.0 × 10^11

so,

now, we can use formula

now, we can plug values

now, we can solve for I

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

y-1700=200(x+4)

step-by-step explanation:

200(x+4) is 200x + 800 she is saving 200 per week x is the weeks and the -1700 is. us that’s howmuch she already had