Step by step how to factor:
2y^2+9y+9=0

Use ac method
for ax²+bx+c=0 when a≠1

multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b

2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that

2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero

y+3=0
y=-3

2y+3=0
2y=-3
y=-3/2

y=-3 and -3/2
it's factored form is (x+3)(2x+3)

Multiple choice or not?