If the product of 6 integers is negative, at most how many of the integers can be negative?
a. 2
b. 3
c. 4
d. 5
e. 6

5. If you multiply a negative by a negative you get a positive, so if you take it in pairs, multiplying 6 negatives is the same as multiplying 3 positives, and therefore the answer is positive, but with 5 negatives an one positive, it is the same as a positive* a negative, and your answer is negative. so 5

Number 5 is 50 degreesnumber 6 is 45 degreesnumber 7 is 60 degreesnumber 8 is 45 degrees

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!