What is the solution to the following system?

Therefore, x = 0 , y = 2 ,z = 5.

Step-by-step explanation:

Given  : Equations .

To find : What is the solution to the following system.

Solution : We have given that

x + 2y + z = 9 (1)

x -y + 3z = 13 (2)

2z = 10 (3)

On dividing by 2 both side on equation 3

z  = 5 .

Plug the value z = 5 in equation (1 )and (2).

x + 2y + 5 = 9

On subtracting both sides by 5

x + 2y = 9 -5

x + 2y = 4 equation(3)

From equation 2

x - y + 3 (5) = 13

x - y + 15 = 13

On subtracting both sides by 15

x -y = -2  equation (4)

On subtracting   equation(4) from equation(3).

x + 2y = 4

(-)x - ( +)y = - (+) 2

0 + 3y =  6

On dividing by 3

y = 2.

Plug y = 2  in equation 3

x + 2( 2 ) = 4

x + 4 = 4.

On  subtracting both sides by 2.

x = 4 - 4

x  =  0 .

Therefore, x = 0 , y = 2 ,z = 5.

where r the answers

step-by-step explanation: