Find the perimeter of parallelogram abcd with vertices a(–5, 6), b(2, 6), c(1, –2), and d(8, –2).

Since in A and B we have the same y value, 2-(-5)=7 and that's one side. For A to C (we connect A to C since they are both the ones on the left), we use the distance formula to get sqrt((-5-1)^2+(6-(-2))^2=sqrt(36+64)=sqrt(100)=10. Since there are 2 equal pairs of sides in a parallelogram, we get 7*2+10*2=34