Given that g(x)=3x²-5x+7 find each of the following
b) g(-2) ** explain how it's squared
c) g(4)
d) g(-x)
e) g(1-t)

G(x) = 3x² - 5x + 7

b) g(-2) ==> Substitude -2 into x

g(-2) = 3(-2)² - 5(-2) + 7
g(-2) = 12 + 10 + 7
g(-2) = 29

c) g(4) ==> Substitude 4 into x

g(4) = 3(4)² - 5(4) + 7
g(4) = 48 - 20 + 7
g(4) = 35

d) g(-x) ==> Substitude -x into x

g(-x) = 3(-x)² - 5(-x) + 7
g(-x) = -3x² + 5x + 7

e) g(1 - t) ==> Substitude 1 - t into x

g(1 - t) = 3(1 - t)² - 5(1 - t) + 7
g(1 - t) = 3(1 - 2t + t²) - 5 + 5t + 7
g(1 - t) = 3 - 6t + 3t² - 5 + 5t + 7
g(1 - t) = 3t² - t + 5