The perimeter of a rectangle is 510 cm. the ratio of the length to the width is 3: 2. what are the dimensions of this rectangle?

The length of the rectangle is 153cm and the width is 102cm

A rectangle is a two-dimensional object with four right angles. It has two diagonals which bisect each other and are of equal length.  

Perimeter of a rectangle = 2 x (length + width)

In order to determine the dimensions of the rectangle, the sum of its sides has to be determine first. The sum of the sides of the rectangle can be determined from its perimeter.

510 cm =  2 x (length + width)

 (length + width) = 510 / 2

(length + width) = 255 cm

The second step is to determine the dimensions

Length = (ratio of length / sum of ratio) x sum of sides

(3/5) x 255 = 153 cm

Width = (ratio of width / sum of ratio) x sum of sides

(2/5) x 255 =102 cm

To learn more about the perimeter of a rectangle, please check: link

depends on how many days you are talking about

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584