Two cars emerge side by side from a tunnel. car a is traveling with a speed of 60km/h and has an acceleration of 40km/h/min. car b has a speed of 40km/h and has an acceleration of 60 km/h/min. which car is passing the other as they come out of the tunnel?

To solve this problem, we have to make use of the formula:

d = v0 t + 0.5 a t^2

What we can do is to assume a time, t = 1 h.

For Car A:

d = 60 * 1 + 0.5 (40 * 60) * 1^2

d = 1,260 km

For Car B:

d = 40 * 1 + 0.5 (60 * 60) * 1^2

d = 1,840 km

Since Car B travelled the larger distance, so it is the Car which passes the other as they come out.

Car B

Car A will pass Car B first when they come out of the tunnel.

       To solve this question, we just need to use simple logic.

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yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it