My friend cant figure this out
the 1/y+9 is 1

y+9

I don't know, I will solve for y
1/y+9-2 is 1 so that prpbably means parenthasees
(1/y+9)-2=1/2 times (y+9)
multiply both sides by 2
2(1/y+9)-4=y+9
add 4 to both sides
2(1/y+9)=y+13
distribute
2/y+18=y+13
subtract 13 from both sides
2/y+5=y
multily both sides by y
2+5y=y^2
subtract 2+5y from both sides
y^2-5y-2=0
if we can factor then assume
if you can factor equation into zy=0 then assume z or/and y=0 so 
use quadratic formula 
in ay^2+by+c=0 then 
y= or 

so subsitute and get 
y=  or  

2(¹/y+9)-4=y+9
2/y+18=y+9+4
2/y+18=y+13
2/y+[18-13]=y
2/y+5=y
2+5y=y²
y²-5y-2

Y=-b±√b²-4ac

2a

y=5±√25-4•1•-2

2

Y=[5+√33]/2

Y=[5-√33]/2

Set up a system of equations