How many liters of water should be added to 18 liters of a 14% bleach so that the remaining solution contains only 10% bleach?

We must take that the 14 % is volumentric. This is we will use only volumetric measures.

From the original solution you can find the quantity of bleach.

Original solution: 18 liters * [14 liters of bleach / 100 liters of solution] = 2.52 liters.

Now you know that those 2.52 liters shall represent the 10% of the new solution, after having added x liters of water. Then:

[2.52 liters of bleach]  / [volume of solution] = 10% = 0.1

=> volume of solution =   2.52 liters  / 0.1 = 25.2 liters of solution.

That tells you that you have to add 25.2 liters - 18 liters =   7.2 liters of water.

Check that in that case you will have:

2.52 liters of bleach

18 liters of the original solution

7.2 liters of new water added to the original solution.

2.52 liters of bleach / [18 + 7.2] liters of solution = 0.1 = 10%.

Then, the answer is: 7.2 liters of water should be added.

meaning it would be x - liters of water ( 0% bleach );
( 18 + x ) * 0.1 = 18 * 0.14 + x * 0
1.8 + 0.1 x = 2.52 + 0
0.1 x = 2.52 - 1.8
0.1 x = 0.72
x = 0.72 : 0.1
x = 7.2 liters
7.2 liters of water should be added

Neither is the answer