this is for 6 !
a total of 68 yd of rope was used to rope off all four sides of a rectangular region with a width of 12 yd. what is the area of the rectangular region?
a) 144 yd
b) 264 yd
c) 484 yd
d) 650 yd

Option B). Area of the rectangular region is 264 yd².

Step-by-step explanation:

It has been given in the question that a 68 yd of rope was used to rope off all four sides of a rectangular region.

Width of the region is 12 yd.

Since length of the rope is the perimeter of the rectangular region.

Therefore 2×(length + width) = 68

2(length + 12) = 68

2×length + 24 = 68

2×length = 68 - 24 = 44

Length = 44/2 = 22 yd

Therefore area of the rectangular region = 22×12 = 264 yd²

Option B) 264 yd² is the region.

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet