#1
what is the distance between the points (4, 7) and (4, –5)?
a.
2 units
b.
12 units
c.
0 units
d.
4 units
#2 what is the distance between the points (–3, 5) and (2, –6)? round your answer to the nearest tenth.
a.
1.4 units
b.
5.1 units
c.
12.1 units
d.
16.0 units
(questions: 3,4 and 5 is the pictures.)

#1   B. 12 Units

#2  

Step-by-step explanation:

For number one it is just adding 5 and 7 together because they both have the same X axis, for number two we have to use the distance formula like this:

                                       d= (x2 - x1)^2 + (y2 - y1)^2

d= (-3 - 2)^2 + (5 - -6)^2

d= (-5)^2 + (-11)^2

d= 25 + 121

d= 146 =  1.46

For 3 through 5 it is the same thing as number 2

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: