Simplify (2x – 2y)(2y + 8) = ? a. 4xy + 16x – 4y2 – 16y b. 4xy – 16x – 4y2 – 16y c. 4xy – 4y2 d. 4xy + 16x + 4y2 + 16y any

(2x-2y)(2y+8)

We take the first number in the first section, and multiply that against each number in the second section.

2x*2y = 4xy
2x*8=16x

So the beginning part of our equation is 4xy + 16x. Now we need to do the second number in the first section the same way. Remember to bring the subtraction sign!!

-2y*2y = -4y^2
-2y*8 = -16y

We add this to the first result:

4xy + 16x -4y^2 -16y (A)

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