Asap find f -1
(picture of equation below)

a. f­-1 (x) = x2 +25; y> 25
b. f ­-1 (x) = x2 + 5; y > 5
c. f ­-1 (x) = (x + 5)2; y > 5
d. f­-1 (x) = x2 +25; y> 5

I.
Given a function f with domain D and range R, and the inverse function 
,

then the domain of is the range of f, and the range of is the domain of f.

II. We are given the function ,

the domain of f, is the set of all x for which makes sense, so x is any x for which x-50, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of  is [0, ∞) and the Range of is [5, ∞) 

III.
Consider

to find the inverse function , 

1. write f(x) as y:



2. write x in terms of y:



take the square of both sides



add 5 to both sides





3. substitute y with x, and x with :



These steps can be applied any time we want to find the inverse function.

IV.  

, x≥0

y≥0, where y are all the values that can take

Remark: the closest choice is B