The vertex and the focus and the directix

Get into form (x-h)²=4p(y-k)
(h,k) is vertex

p is disatnace from focus to vertex and vertex to directix

if p is negative, then directeix is above focus
if p is positive the directix is below focus

so
x²+20y=10
x²=-20y+10
(x-0)²=4(-5)(y-0.5)
vertex is (0,0.5)
-5<0 so directix is above focus and above the vertex
it is 5 units above the vertex
so it is at y=5.5
the focus is 5 units below the vertex
it is at (0,-4.5)

vertex is (0,0.5)
focus is (0,-4.5)
directix is y=5.5