How do you solve 3x+4y=12 and 2x=y-6

3x +4y =12

2x = y-6 Rewrite this as y = 2x+6

 now replace that for y in the first equation

3x + 4(2x+6) = 12

now do all the calculations:

3x + 8x +24 =12

11x + 24 = 12

11x = -12

x = -12/11 = -1 1/11

 now substitute -12/11 for x in the 2nd equation and solve

y = 2x+6

y = 2(-1 1/11) +6

y = 42/11 = 3 9/11

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13