Aspinner has 12 equal sectors with different letters for each sector, as shown below: a spinner with 12 equal sectors is shown. the sectors are labeled b, y, g, c, p, o, v, m, a, d, e, and r. hamlet spins the spinner 5 times, and it stops at the letter b 4 times. if he spins the spinner a 6th time, what is the theoretical probability that this time it will stop at the letter b? 1 over 12 1 over 10 1 over 5 1 over 4

The theoretical probability that in the 6th time the spinner will stop at the letter B is:

                        1 over 12.

It is given that:

A spinner with 12  are labeled B, Y, G, C, P, O, V, M, A, D, E, and R.

Hamlet spins the spinner 5 times, and it stops at the letter B 4 times.

Now, we are asked to find the probability that the spinner will stop at the letter B for the 6th time.

Now, we know that each of the outcome is independent of the other.

Since, the outcome for the first 4 spins are fixed.

Hence, the probability of first four spin is: 1

Hence, the probability that the spinner will stop at letter B this time is:

                  1 over 12.

( Since, there are a total of 12 outcomes possible while spinning a spinner and only in one sector there is a letter B)

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.