How to find the product property of square roots. the question is the square root of 9 ÷ over the square root of 18? show me the steps.

9÷√18 in simplified form gives me 9÷3√2. You cannot have a square root in the denominator so multiply both numerator and denominator by √2 which results in 9√2÷3√2*√2= 9√2÷6 and simplified to 3√2 ÷2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

unless if u could do my questions, if not i wouldn't want to