The longest side of an obtuse triangle measures 20 cm. the two shorter sides measure x cm and 3x cm.

rounded to the nearest tenth, what is the greatest possible value of x?

6.3
6.4
7.0
7.1

If an obtuse triangle is given and 20 cm is the longest side, then: 

x² + (3x)² < 20²
x² + 9x² < 400
10x² < 400
x² < 40
x < 6.3

So, the greatest possible value of x could be 6.29999... ≈ 6.3 to the nearest tenth.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!