The sum of three numbers is 123. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. find the three numbers.

A+b+c=123
b=2a-9
c=3a+6

Substitute the values of b and c into the first equation

a+(2a-9)+(3a+6)=123

Combine like terms

6a-3=123
6a=126
a=21

Plug this a value into the second and third equation to get the b and c values.

b=2(21)-9
b=42-9
b=33

c=3(21)+6
c=63+6
c=69

Final
a=21
b=33
c=69

Ithink d, not completely sure sorry