Write x2 - 12x + 8 = 0 in vertex form.

(x-4)^2-19=y
you first add the three to the other side, then add 16 on both sides, make the left side x-4 squared, and lastly you subtract 19 from both sides.

I have not learned this stuff yet, but by using online calculators, I can determine that the vertex form of your equation is:

n/a. It cannot be written in vertex form because it is not a conic section.

But if you are referring to x^2 - 12x + 8, the answer is: Y = (x - 6)² - 28 (i think)