Express the following question in the form of a + bi. (3+5i)i (-2-7i)

31+29i

step 1) (3+5i)i
            (3i+5i^2)      i^2 = -1
            (3i+ 5(-1) = (3i-5)

step 2 (FOIL)   (3i-5)(-2-7i) = -6i-21i^2+10+35i

step 3) (simplify)        (-6i+35i) +(-21i^2 +10) = (-6i+35i) +(21+10) = 31+29i
                                   

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3