Alarge grocery store received an order of 2000 apples a neighboring school received an order of 20 boxes of apples with 100 apples and each use disk or disk on a place value chart to compare the number of apples received by the school and the number of apples received by the grocery store

Disk on a place value chart to compare the number of apples received by the school and the number of apples received by the grocery store is shown below:

           Thousands      Hundreds      tens      ones

Store        ⊕⊕

School      ⊕⊕

Step-by-step explanation:

Consider the provided information.

A large grocery store received an order of 2000 apples.

Here 2 is at the thousands place.

We need to use disk on a place value chart.

We will use "⊕" as a disk.

With the help of disk we can write the number 2000 in place value chart as shown below:

           Thousands      Hundreds      tens      ones

Store        ⊕⊕

With the help of number it can be written as

           Thousands      Hundreds      tens      ones

Store          2

Now, it is given that a neighboring school received an order of 20 boxes of apples with 100 apples

Each box has 100 apples and there are 20 such boxes, that means the total number of apples are:

20 × 100 = 2000

Thus there are again 2000 apples.

Here 2 is at the thousands place.

We need to use disk on a place value chart.

With the help of disk we can write the number 2000 in place value chart as shown below:

           Thousands      Hundreds      tens      ones

Store        ⊕⊕

School      ⊕⊕

With the help of number it can be written as

           Thousands      Hundreds      tens      ones

Store          2

School       2

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1