An ant looks up to the top of a tree with an angle of elevation of 38. if the ant is 43 feet from the base of the tree, what is the height of the tree, to the nearest tenth?
a. 33.6 feet
b. 34.1 feet
c. 35.4 feet
d. 38.5 feet

33.6 feet

Step-by-step explanation:

Given : An ant looks up to the top of a tree with an angle of elevation of 38.

To Find:  If the ant is 43 feet from the base of the tree, what is the height of the tree, to the nearest tenth?

Solution:

Refer the attached figure

An ant looks up to the top of a tree with an angle of elevation of 38.i.e.∠ACB= 38°

The ant is 43 feet from the base of the tree i.e.BC = 43 feet.

Now we are supposed to find the height of the tree i.e. AB

Now we will use trigonometric ratio

Hence the height of the tree is 33.6 feet.

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!